in the given figure ab parallel CD find the value of x
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AB || CD [ given ]
<A = <C [ corresponding angle ]
75° = 75°
<C + <C' = 180° [ straight angle or linear pair ]
75° + <C' = 180°
<C' = 180° - 75°
= 105°
Now,
sum of all angles of triangle = 180°
<C' + <F + <E = 180°
105° + 30° + x = 180°
x = 180° - 135°
= 45°
....... hope it helps you..............
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