Math, asked by cvbiyer, 8 months ago

4. Find the value of b such that the quadratic equation (b-3)x2 + 4(b-3)x +4=0 has equal roots.

Answers

Answered by Anonymous

1

Discriminant = 0

b² -4ac = 0

[4(b-3)]² - 4×(b-3)(4) =0

16(b - 3)( b-4 ) = 0

b = 3, 4

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