Question

4. Find the value of b such that the quadratic equation (b-3)x2 + 4(b-3)x +4=0 has equal roots.

Answer 1

Discriminant = 0

b² -4ac = 0

[4(b-3)]² - 4×(b-3)(4) =0

16(b - 3)( b-4 ) = 0

b = 3, 4