Question

4. Five years ago, a mother was seven times as old as her daughter. Five years
hence, she will be three times as old as her daughter. Find their present ages.​

Answer 1

Let the present age of the daughter be 'x'. But according to the question, after 5 years, mother will be thrice daughter's age.

�• Daughter's present age = x = 10 years.

�• Mother's present age = 7x - 30 = 7(10) - 30 = 70 - 30 = 40 years.

orr

Let the mothers age be M and the daughters D

M - 5 = 7(D-5)

M = 7D - 30

M + 5 = 3(D + 5)

M = 3D + 10

so

7D - 30 = 3D + 10

4D = 40

D = 10 (Daughter is currently 10 years old)

M = 3D + 10

M = 40 (Mother is currently 40)

miss sharabi (◍•ᴗ•◍)❤

Answer 2

Answer:

10 years and 40 years

Step-by-step explanation:

Let the present age of the daughter be 'x'.

Then, 5 years ago,

Daughter's age = x - 5

Mother's age = 7(x - 5) = 7x - 35

Then, at present,

Daughter's age = x - 5 + 5 = x

Mother's age = 7x - 35 + 5 = 7x - 30

And, 5 years hence,

Daughter's age = x + 5

Mother's age = 7x - 30 + 5 = 7x - 25

But according to the question, after 5 years, mother will be thrice daughter's age.

→ 7x - 25 = 3(x + 5)

=> 7x - 25 = 3x + 15

=> 7x - 3x = 15 + 25

=> 4x = 40

=> x = 40/4

=> x = 10

Hence, Daughter's present age = x = 10 years.

and,

Mother's present age = 7x - 30 = 7(10) - 30 = 70 - 30 = 40 years.

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