Question

4. From the following figure, find the values of :
H.T(i) sin B
(ii) tan c
(iii) sec2 B - tan? B (iv) sin’C + cos2 C
A
13
B
D
------5----
-16--
answer for Cos B and Cot C​

Answer 1

Answer:

Given that

Tan(cos inverse of x )          =  

sin (cos inverse of 1/2)

i.e sin ( cos inverse of 1/2) =  

sin (sin inverse of pie - 1/2)

                                                = pie by 2

Therefore  

Tan (cos inverse of x)          =  pie by 2

Cos inverse of x                    =    

tan inverse of pie by 2

We know that tan inverse of pie by 2 =0

Therefore  cos inverse of x =0  

i.e, x=pie by 2

Step-by-step explanation: