Math, asked by adit456soni, 1 month ago

6. Add the following:
(i) 4p(2 - p2) and 8p3 – 3p
(ii) 7xy(8x + 2y – 3) and 4xy?(3y – 7x + 8)
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Answers

Answered by Anonymous
5

\huge\fcolorbox{cyan}{black}{Answer}

Solution 1

➦ 4p(2 - p²) and 8p³– 3p

➦ 8p - 4p³ and 8p³ - 3p

➦ 8p - 4p³ + 8p³ - 3p

➦ 8p - 3p + 8p³ - 4p³

➦ 5p + 4p³

4p³ + 5p

___________________

Solution 2

➦ 7xy(8x + 2y – 3) and 4xy(3y – 7x + 8)

➦ 56x²y + 14xy² - 21xy and 12xy² - 28x²y + 32xy

➦ 56x²y + 14xy² - 21xy + 12xy² - 28x²y + 32xy

➦ 56x²y - 28x²y + 14xy² + 12xy² + 32xy - 21xy

28x²y + 26xy² + 11xy

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Answered by BrainlyArnab
4

Answer:

(i) 5p+4p³ = p(5+4p²)

(ii) 28x²y + 26xy² + 11xy = xy(28x+26y+11)

Step-by-step explanation:

find the sum :-

(i) 4p(2-p²) and 8p³-3p

= (4p×2) + {4p×(-p²)} and 8p³-3p

= 8p+(-4p³) + 8p³-3p

= 8p-4p³+8p³-3p

= 8p-3p +8p³-4p³

= 5p+4p³

= p(5+4p²)

p common in both.

(ii) 7xy(8x+2y-3) and 4xy(3y-7x+8)

= (7xy×8x) + (7xy×2y) -(7xy×3) and (4xy×3y) -(4xy×7x) + (4xy×8)

= 56x²y +14xy² -21xy +12xy²-28x²y+32xy

= 56 y -28x²y +14xy²+12xy²+32xy-21xy

= 28x²y + 26xy² + 11xy

= xy(28x+26y+11)

xy common amon polynomials.

hope it helps.

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