Question

4 g of a metal oxide contain 1.6 g oxygen,then the equivalent mass of the metal

Answer 1

The metal oxide is MgO sice the mass of magnesium is 24 g and mass of oxygen is 16 g.
Here, 40 g of MgO contains 16 g of Oxygen and hence, 4 g of MgO will contain 1.6 g of oxygen.
Since, Mg is a divalent metal, hence, the equivalent mass of Mg2+ is (24/2)g= 12 g

Answer 2

The equivalent mass of the metal is 12 g

Given data:

Mass of metal oxide  =  4 g

Mass of oxygen = 1.6 g

Mass of metal  =  4 - 1.6  = 2.4 g

Solution:

$Equivalent\quad mass\quad =\quad \left( \frac { mass\quad of\quad metal }{ mass\quad of\quad oxygen } \right) \quad \times \quad equivalent\quad mass\quad of\quad oxygen$

Plug the value in the given formula:

$Equivalent\quad mass =\quad \left( \frac { 2.4\quad g }{ 1.6\quad g } \right) \quad \times \quad 8\quad =\quad 12\quad g$