4 g of CH4 was burnt in O2 to give co2and H2O. What is the volume of CO2 obtained at S.T.P
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Answer is 5.6 L of CO2...........
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CH4 + 2O2 -> CO2 + 2H2O
Mole = mass/ molar mass
Molar mass of CH4 = 12+ 4 = 16 g
Mole of CH4 = 4/16 = 1/4 mole
1 mole of CH4 gives 1 mole of CO2
1/4 mole of CH4 gives 1/4 mole of CO2
Mole = volume /22.4
Mole×22.4 = volume
1/4 ×22.4 = volume
22.4 / 4 = volume
5.6 l = Volume
Therefore volume of CO2 obtained at STP is 5.6 litre
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