Question

4. Given that DAB is a straight line, tied the values/of the unknowns in each of the following figures​

Answer 1

Given :-

Triangle BCD and AC is perpendicular to BD

Solution :-

In a ΔABC,

ΔA = 90°

ΔB = C°

ΔC = 35°

As we know that,

The sum of interior angles of triangles is 180°

Now,

By using Angle sum property,

ΔA + ΔB + ΔC = 180°

Put the required values,

90° + c° + 35° = 180°

125 + c° = 180°

c° = 180 - 125

c° = 55°

In ΔACD

Using Angle sum property,

ΔA + ΔC + ΔD = 180°

90° + b° + 50° = 180°

120° + b° = 180°

b° = 180° - 140°

b° = 40°

Hence, The value of b° = 40° and

c= 55$.$

Answer 2

Correct Question-:

• Given that Δ DAB is a straight line . Find the values of the unknowns in each of the following figures.

AnswEr-:

♤ The value of Unknown Values are -: ♤

• B = 40⁰
• C= 55⁰

Explanation-:

By Analysing the figure we can see that -:

• In ΔADC -:
• ΔA = 90⁰ ,
• ΔC = b⁰ and
• ΔD= 50⁰

As we know that ,

• Sum of Interior angles of Triangle is 180⁰ .
• = 》 ΔD + ΔC + ΔA = 180⁰

Here ,

• ΔD = 50⁰
• ΔC = b⁰
• ΔA = 90⁰

Now ,

• : = 》 ΔD + ΔC + ΔA = 180⁰
• : = 》 50⁰ + b⁰ + 90⁰ = 180⁰
• : = 》 140⁰ + b⁰ = 180⁰
• : = 》 b⁰ = 180⁰ - 140⁰
• : = 》 b⁰ = 40⁰

Therefore,

• B = 40⁰

In Second Case -:

By Analysing the figure we can see that -:

• By Analysing the figure we can see that -: In ΔABC -:
• ΔA = 90⁰ ,
• ΔB = c ⁰ and
• ΔC= 35⁰

As we know that ,

• As we know that ,
• Sum angles of Triangle is 180⁰ .
• = 》 ΔA + ΔB + ΔC = 180⁰

Here ,

• ΔA = 90⁰
• ΔB = c⁰
• ΔC = 35⁰

• : = 》 ΔA + ΔB + ΔC = 180⁰
• : = 》 35⁰ + 90⁰ + c⁰ = 180⁰
• : = 》 125⁰ + c⁰ = 180⁰
• : = 》 c⁰ = 180⁰ - 125⁰
• : = 》 c⁰ = 55⁰

Therefore,

• C = 55⁰

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Hence ,

♤ The value of Unknown Values are -: ♤

• B = 40⁰
• C= 55⁰

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