Question

4 HCl(g) + O2(g) + 2H₂O₁₁ + 2Cl₂ AH = ? Calculate enthalpy change of above reaction from following data. Haigs + / 02(g) →→→ H₂O(g) AH = -2858 KT AH=-407 KT 2H2O(l) = 2H2O (g) AH-185 KT H₂(g) + Cl₂ (g) =2HCL(g)​

Answer 1

Explanation:

ΔH

o

=ΔH

f(products)

o

−ΔH

f(reactants)

o

=[ΔH

(CO

2

)

o

+ΔH

(H

2

O)

o

]−[ΔH

(CH

4

)

o

+2ΔH

(O

2

)

o

]

=[−393.5+2×(−286.2)]−[−74.8+2×0]=−890.7kJ