Question

the electronic configuration of two elements are given below. answer the following questions with the help of the given electronic configuration.
1s^2,2s^2,2p^2,3s^2, and 1s^2,2s^2,2p^2,3s^2, 3p^5
a) name these elements
b)in which group, period and block do these elements belong to
c) write the molecular formula of a compound formed by the combination of these elements.
d)what type of a bond is formed between them and why?

i desperately need the answers :>

Answer 1

Answer:

(i) (A) Mg (Z=12) (B) Ne (Z=10) (C) N (Z=7) (D) Na (Z=11) (E) F (Z=9)

(ii) D: Na is alkali metal.

(iii) E: F belongs to the halogen.

(iv) D: Na is alkali metal.

(v) B: Ne an inert gas.

Answer 2

Explanation:

HEY MATE YOUR ANSWER IS HERE ^_^

THE GIVEN ELECTRONIC CONFIGURATION IS WRONG STILL I WILL ANSWER

(1) FIRST HAS 8 ELECTRONS IT IS OXYGEN

SECOND HAS 13 ELECTRONS IT IS ALUMINIUM

(2)OXYGEN BELONGS TO 16TH GROUP, 2ND PERIOD & P-BLOCK

ALUMINIUM BELONGS TO 14TH GROUP 3RD, PERIOD & P-BLOCK

(3) Al2O3

(4) THE COVALENT BOND IS FORMED BETWEEN THEM BECAUSE BOTH ARE NON METALS (ALUMINIUM IS AMPHOTERIC METAL).

PLEASE MAKE ME A BRAINLIEST ANSWER FOR THE QUESTION.