Question

4. How much carbon dioxide i liberated
when 50gm of calcium carbonate reacts
with excess of hydrochloric acid.
[ca=40 U, C = 120,0 = 160, H = 0,01 = 35.50)​

Answer 1

CaCO3 +2HCl =====> CaO+ H2O +CO2

[Molecular weight of CaCO3= 100 ]

So 100 g of CaCO3 on treating with excess of HCl will liberate= 44g of CO2.

Therefore 50 g of CaCO3 will liberate =22 g of CO2

= 11.2 Litres of CO2 gas at STP

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