Question

4. If 10g of ice at 0°C is mixed with 10g of water
at 10°C, the final temperature is given by
(a) 10 x 80 + 10(-0) = 10(10-t)
(b) 10 x 80 = 10(10-t) + 10(-0)
(c) 5°C
(d) 0°C​

Answer 1

Answer:

A

Explanation:

heat consume by water=heat absorb by ice

MS(water) (T2-T1) = MS(ice) (T2-T1) + MLf

masses of water and ice both are same.

10(10- t) = 10(-0) + 10×80