Question

4. If 2 sin theeta - 1 = 0, then prove that
sec theeta + tan theeta = √3.​

Answer 1

Given :

2sinϴ - 1 = 0

To prove :

secϴ + tanϴ = √3

Proof :

We have ,

=> 2sinϴ - 1 = 0

=> 2sinϴ = 1

=> sinϴ = 1/2

=> sinϴ = sin30°

=> ϴ = 30°

Now ,

=> secϴ + tanϴ = sec30° + tan30°

=> secϴ + tanϴ = 2/√3 + 1/√3

=> secϴ + tanϴ = (2 + 1)/√3

=> secϴ + tanϴ = 3/√3

=> secϴ + tanϴ = √3

Hence proved .