4. If A = {4,6,7,8,9}, { B = 2,4,6} and C = {1,2,3,4,5,6}, then find
(i) A+(B+C) (ii) A+(B + C) (iii) A\(C\B)
Answers
Answered by
2
Question:
If A = {4,6,7,8,9} , B = {2,4,6} and C = {1,2,3,4,5,6},then find
(i) A U (B ∩ C) (ii) A ∩ (B U C) (iii) A \ (C \ B)
Union of two sets :
The union of the sets A and B is the set of all the element that belongs to either A or B or both. It is denoted by A U B(“A union B”).
Intersection of two sets :
The intersection of the sets a and b is the set of all the elements which belong to both A and B. It is denoted by A ∩ B (“ A intersection B”).
•if a and b do not have any element in common then A ∩ B= a null set = Ø
SOLUTION:
(i) A U (B ∩ C)
(B ∩ C) = {2,4,6} ∩ {1,2,3,4,5,6}
= {2,4,6}
A U (B ∩ C) = {4,6,7,8,9} U {2,4,6}
A U (B ∩ C) = {2,4,6,7,8,9}
(ii) A ∩ (B U C)
(B U C) = {2,4,6} U {1,2,3,4,5,6}
= {1,2,3,4,5,6}
A ∩ (B U C) = {4,6,7,8,9} ∩ {1,2,3,4,5,6}
A ∩ (B U C) = {4,6}
(iii) A \ (C \ B)
C \ B = {1,2,3,4,5,6} \ {2,4,6}
= {1,3,5}
A \ (C \ B) = {4,6,7,8,9} \ {1,3,,5}
A \ (C \ B) = {4,6,7,8,9}
HOPE THIS WILL HELP YOU….
If A = {4,6,7,8,9} , B = {2,4,6} and C = {1,2,3,4,5,6},then find
(i) A U (B ∩ C) (ii) A ∩ (B U C) (iii) A \ (C \ B)
Union of two sets :
The union of the sets A and B is the set of all the element that belongs to either A or B or both. It is denoted by A U B(“A union B”).
Intersection of two sets :
The intersection of the sets a and b is the set of all the elements which belong to both A and B. It is denoted by A ∩ B (“ A intersection B”).
•if a and b do not have any element in common then A ∩ B= a null set = Ø
SOLUTION:
(i) A U (B ∩ C)
(B ∩ C) = {2,4,6} ∩ {1,2,3,4,5,6}
= {2,4,6}
A U (B ∩ C) = {4,6,7,8,9} U {2,4,6}
A U (B ∩ C) = {2,4,6,7,8,9}
(ii) A ∩ (B U C)
(B U C) = {2,4,6} U {1,2,3,4,5,6}
= {1,2,3,4,5,6}
A ∩ (B U C) = {4,6,7,8,9} ∩ {1,2,3,4,5,6}
A ∩ (B U C) = {4,6}
(iii) A \ (C \ B)
C \ B = {1,2,3,4,5,6} \ {2,4,6}
= {1,3,5}
A \ (C \ B) = {4,6,7,8,9} \ {1,3,,5}
A \ (C \ B) = {4,6,7,8,9}
HOPE THIS WILL HELP YOU….
Answered by
0
Hi,
It is given that,
A = { 4, 6, 7, 8 , 9 }
B = { 2 , 4 , 6 }
C = { 1, 2 , 3 , 4, 5 , 6 }
****************************************
we know that ,
A U B = { x / x € A or x € B }
A and B = { x / x € A and x € B }
A/B = { x /x € A and x doesn't belongs to B }
*****************************************
i ) A U ( B U C )
= A U ( { 2, 4 , 6 } U { 1, 2 , 3 , 4 , 5 , 6 } )
= A U { 1 , 2 , 3 , 4 , 5 , 6 }
= { 4, 6, 7 , 8 , 9 } U { 1,2,3,4,5,6 }
= { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 } ---( 1 )
ii ) ( A U B ) U C
= ( { 4,6,7,8,9 } U { 2,4,6 } ) U C
= { 2,4,6,7,8,9 } U C
= { 2,4,6,7,8,9 } U { 1,2,3,4,5,6}
= { 1,2,3,4,5,6,7,8,9 } ---( 2 )
from ( 1 ) and ( 2 ) , we conclude that
A U( B UC ) = ( A U B ) U C
[ associative proporty ]
iii )
A\( C\B )
= A \ ( { 1,2,3,4,5,6 } \{ 2, 4 ,6 })
= A \ { 1 , 3 , 5 }
= { 4, 6 , 7 , 8 , 9 } \ { 1 , 3 , 5 }
= { 4 , 6, 7 , 8 , 9 }
I hope this helps you.
: )
It is given that,
A = { 4, 6, 7, 8 , 9 }
B = { 2 , 4 , 6 }
C = { 1, 2 , 3 , 4, 5 , 6 }
****************************************
we know that ,
A U B = { x / x € A or x € B }
A and B = { x / x € A and x € B }
A/B = { x /x € A and x doesn't belongs to B }
*****************************************
i ) A U ( B U C )
= A U ( { 2, 4 , 6 } U { 1, 2 , 3 , 4 , 5 , 6 } )
= A U { 1 , 2 , 3 , 4 , 5 , 6 }
= { 4, 6, 7 , 8 , 9 } U { 1,2,3,4,5,6 }
= { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 } ---( 1 )
ii ) ( A U B ) U C
= ( { 4,6,7,8,9 } U { 2,4,6 } ) U C
= { 2,4,6,7,8,9 } U C
= { 2,4,6,7,8,9 } U { 1,2,3,4,5,6}
= { 1,2,3,4,5,6,7,8,9 } ---( 2 )
from ( 1 ) and ( 2 ) , we conclude that
A U( B UC ) = ( A U B ) U C
[ associative proporty ]
iii )
A\( C\B )
= A \ ( { 1,2,3,4,5,6 } \{ 2, 4 ,6 })
= A \ { 1 , 3 , 5 }
= { 4, 6 , 7 , 8 , 9 } \ { 1 , 3 , 5 }
= { 4 , 6, 7 , 8 , 9 }
I hope this helps you.
: )
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