Math, asked by daivadnyapavitra, 7 months ago

4. If all the sides of a
parallelogram touch a
circle, then prove that it
is a
rhombus.
5. If the angle between
two radii of a circle is
1300, then find the angle
between the tangents
at the eruds of the radii.
6. Two concentric circles
of radii a and b (a > b) are
given. Find the length of
the chord of larger
circle which touches the
smaller circle​

Answers

Answered by kislayasrivastava
0

Answer:

here is your answer

Step-by-step explanation:

Given : Sides AB,BC,CD andDA of a parrallelogram ABCD touch a circle at P,Q,Rand S respectively.

To prove : Parallelogram ABCD is a rhombus.

Proof :

SinceTangents drawn from an external point to a circle are equal

AP=AS.....(1)(Tangent from point A )

BP=BQ....(2)(Tangent from point B )

CR=CQ....(3)(Tangent from point A )

DR=DS....(4)(Tangent from point A )

Adding (1), (2), (3) and (4), we get

AP+BP+CR+DR=AS+BQ+CQ+DS

(AP+BP)+(CR+DR)=(AS+DS)+(BQ+CQ)

AB+CD=AD+BC

AB+AB=AD+AD [In a Parallelogram ABCD, opposite sides are equal]

2AB=2ADorAB=AD

But AB=CDandAD=BC [Opposite sides of a Parallelogram are equal]

AB=BC=CD=DA

Hence, Parallelogram ABCD is a rhombus.

Answered by neelamsinghchauhan77
0

Answer:

Here's the 4th one mate !

Have a look at the photo I've attached !

I HOPE IT'S HELPFUL !

I HOPE IT'S HELPFUL !HAVE A GREAT DAY !

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