Question

4. If in a right angle triangle height is twice the base and hypotenuse is
125cm. then find its remaining two sides.​

Answer 1

Answer:

55.9 cm , 111.8 cm ( approximate values  rounded off to 2 decimal digits )

Step-by-step explanation:

let base be x cm

let height be 2x cm

hypotenuse = 125 cm

then by pythagoras theorem

x² + ( 2x )² = 125²

=> x²  + 4x² = 15625

=> 5x² = 15625

=> x² = 15625 / 5 = 3125

x = $\sqrt{3125}$

=55.90 cm

therefore base = 55.9 cm

height = 2* 55.9 = 111.8 cm

pls mark brainliest

Answer 2

given

in a right angle triangle height is twice the base and hypotenuse is

125cm

let height of triangle be h

let base be b

given h=2b

in a right angled the sum of squares of base and height is equal to square of hypotenuse

h^2+b^2=125^2

5b^2=125^2

b^2=3125

b=55.9

h=111.8

hope this helps you

please mark the answer as brainliest please

please FOLLOW me