Question

4. If in a triangle ABC, 2 cos A = sin B cosec C, then
(a) a= b
(b) b = c
(c) c=a
(d) 2a= bc​

Answer 1

Step-by-step explanation:

I don't understand sorry bro

Answer 2

2(b^2+c^2-a^2/2bc)=b/2r.2r/c

b^2+c^2-a^2/bc=b/c

C^2=a^2

C=a