Question

4.
If in the given circuit Xc = 200 2 and XL = 350 22
then the effective current through the source is

(1) 5 A
(2)3/2A
(3) 2/3A
(4) 2A​

Answer 1

Answer:1)5A

Hope it helps

Answer 2

The effective current through the source is 2 A.

Explanation:

Given that,

Voltage of the circuit, V = 300 V

Capacitive reactance, $X_c=200\ \Omega$

Inductive reactance, $X_L=350\ \Omega$

Firstly, we will find the impedance of the LC circuit. It is given by :

$Z=\sqrt{R^2+(X_L-X_c)^2} \\\\Z=\sqrt{0^2+(350-200)^2}\\\\Z=150\ \Omega$

Let I is the effective current through the source. It is given by using Ohm's law :

$V=IZ\\\\I=\dfrac{V}{Z}\\\\I=\dfrac{300}{150}\\\\I=2\ A$

So, the effective current through the source is 2 A. Hence, this is the required solution.

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