Math, asked by kaashvireddy5, 7 months ago

4) If one angle of a parallelogram is 40°, what are the measures of the other angles?

Plz and step by step and don't ans do it on your own and all that plz
need it fast​

Answers

Answered by pandaXop
50

Angles = 140° , 140°

Step-by-step explanation:

Given:

  • Measure of one angle of parallelogram is of 40°.

To Find:

  • What are the measures of other angles?

Solution: Let ABCD be a || gm and measure of other two angles be .

[ A Parallelogram is type of quadrilateral in which opposite sides are parallel and opposite angles are equal to each other ]

Therefore,

  • ∠A = ∠C = 40°
  • ∠B = ∠D = x°

As we know that

Sum of all angles of ||gm = 360°

\implies{\rm } A + B + C + D = 360°

\implies{\rm } 40° + x + 40° + x = 360°

\implies{\rm } 80° + 2x = 360°

\implies{\rm } 2x = 360° 8

\implies{\rm } 2x = 280°

\implies{\rm } x = 280°/2°

\implies{\rm } x = 140

Hence,

➬ ∠A = ∠C = 40° and

➬ ∠B = ∠D = 140°

Attachments:

Anonymous: Awesome ^^"
shadowsabers03: Great!
Answered by rohit301486
123

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{angles \: of \: parrellelogram \: are \angle{Q} \:  -  {110}^{0} \:   \angle{R} -  {7 0 }^{0} \: and \:  \angle{S} -  {110}^{0}   }}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline \bold{Given :}}

\tt : \implies  one \:  angle \:  of \:   a \:  parallelogram  \: is \:   {40}^{0}

\red{\underline \bold{To \: Find :}}

\tt : \implies what \:  are \:  the \:  measures  \: of  \: the  \: other \:  angles?

  • Given Question

\tt : \implies \: let \: the \: parrellelogram \: be \: PQRS

\tt : \implies \angle{P} - 7 0(given)

\tt : \implies \angle{R} - 70(opposites \: angle \: of \: parrllelogram \: are \: equal

\tt : \implies \angle{P} +  \angle{Q} = 180

 \tt : \implies\angle{P} = 70

 \tt : \implies\angle{Q} + 70 - 180

 \tt : \implies\angle{Q} = 180 - 70

 \tt : \implies\angle{Q} = 110

\tt : \implies \angle{Q} =  \angle{S}

\tt : \implies \angle{Q} \:  and \: are \: equal \:   \angle{S}

\tt : \implies\angle{S} = 110

\green{\tt{\therefore{angles \: of \: parrellelogram \: are \angle{Q} \:  -  {110}^{0} \:   \angle{R} -  {7 0 }^{0} \: and \:  \angle{S} -  {110}^{0}   }}}


Anonymous: Nice ^^"
shadowsabers03: Great!
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