Question

x
$x ^{2} - 7x + 10$
find the zeroes and make realation between them.​

Answer 1

Answer:

5 , 2

Step-by-step explanation:

$given \\ a {x}^{2} + bx + c = 0 \\ \\ \alpha \: and \: \beta \: their \: zeroes \\ \\ = > \alpha + \beta = - \frac{b}{a} \\ \\ = > \alpha \beta = \frac{c}{a} \\ \\ now \ \ \\ {x}^{2} - 7x + 10 = 0 \\ \\ \alpha + \beta = 7 \\ \\ \alpha \beta = 10 \\ \\ = > {x}^{2} - 7x + 10 = 0 \\ \\ = > {x}^{2} - 5x - 2x + 10 = 0 \\ \\ = > x(x - 5) - 2(x - 5) = 0 \\ \\ = > (x - 5)(x - 2) = 0 \\ \\ = > \alpha = 5 \\ \\ = > \beta = 2$

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Answer 2

Answer:

5 and 2

Step-by-step explanation:

${x}^{2} - 7x + 10 = 0$

=(x-5)(x-2)