Question

4) If one root of the quadratic equation kx2 - 7x + 5 = 0 is 1, then find then value of k.​

Answer 1

Answer:

k*1*2-7*1+5=0

2k-7+5=0

2k-2=0

2k=2

k=2/2

hence k=1

Step-by-step explanation:

Answer 2

Answer:

p(x) = kx^2 - 7x + = 0

k = 2

Step-by-step explanation:

p(x) = kx^2 - 7x + 5 = 0

p(1) =k*(1)^2 - 7*1 + 5 = 0

=>k - 7 +5 = 0

=>k - 2 = 0

=>k = 2