Question

4./ If sin x = cos²x, then write the value of

${cosx}^{2}$(1 + cos²x).​

Answer 1

Answer:

cos²x(1+cos²x)

=> sinx(1+sinx)

=> sinx + sin²x

=> cos²x + sin²x

=> 1

Answer 2

$\sin(x) = { \cos(x) }^{2} \\ { \cos(x) }^{2} \: \: \: \: {1 + { \cos(x}) }^{2} \\ \sin(x) \: \: \: \: \: \: 1 + \sin(x) \\ \sin(x) + { \sin(x) }^{2} \\ { \cos(x) }^{2} + { \sin(x) }^{2} \\ 1$