Math, asked by rockinboy54, 9 days ago

4. If x = -y and y> 0, which of the following is wrong? (a) x²y > 0 (b) x+y=0 (C) xy < 0 (d) 1/x-1/y=0​

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Answered by savitasharwan
0

Answer:

Correct answer = (d) 1/x - 1/y = 0 Given: x = -y and y > 0 Now, we have: (i) x2 y On substituting x = -y, we get: (-y)2 y = y3 > 0 (∵ y > 0) This is true. (ii) x + y On substituting x = -y, we get: (-y) + y = 0 This is also true. (iii) xy On substituting x = -y, we get: (-y)y = -y2 (∵ y > 0) This is again true. (iv) 1/x - 1/y = 0 ⇒ y−x/xy = 0 On substituting x = -y, we get: y−(−y) (−y)y = 0 ⇒ 2y/−y2 = 0 ⇒ 2y = 0 ⇒ y = 0.Read more on Sarthaks.com - https://www.sarthaks.com/1115917/if-x-y-and-y-0-which-of-the-following-is-wrong

Answered by noorahamdks
1

Answer:

option a is correctly there

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