Question

4.If x2-y2=16 and (x+y)=8 then (x-y) is​

Answer 1

Answer:

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Step-by-step explanation:

What if x^2-y^2=16 and x+y=8 then x-y=?

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x^2 - y^2 = 16

x + y = 8

Solve the second equation for x or y. I will solve for x.

x + y = 8

-y = -y subtract y from both sides of equation

x = 8 - y

Now substitute the value of x we just found into the first equation and solve for y.

(8-y)^2 - y^2 = 16

64 -16y +y^2 - y^2 = 16 FOIL the (8-y)^2 and simplify

-16y + 64 = 16 Combine like terms

-y + 4 = 1 Divide each term by 16 to reduce it

-y = -3 Subtract 4 from both sides

y = 3 Divide both sides by the -1

Now substitute the 3 in for y in the original equations and find x.

x + y = 8 or x^2 - y^2 = 16

x + 3 = 8 or x^2 - (3)^2 = 16

x = 5 or x^2 - 9 = 16 so x^2 = 25, so x = 5

If x = 5 and y = 3; then x - y = 5 - 3 which is 2

x - y = 2

Answer 2

Step-by-step explanation:

Given:

${x}^{2} - {y}^{2} = 16 \\ x + y = 8$

To find: Find the value of (x-y).

Solution:

We know that

$\bold{(a + b)(a-b) = {a}^{2} - {b}^{2}}$

So,

Apply this identity into first equation

$(x + y)(x - y) = 16$

we have (x+y)=8 in second equation.

Place this value

$8(x - y) = 16 \\ \\ (x - y) = \frac{16}{8} \\ \\ (x - y) = 2$

Final answer:

$\bold{\red{(x - y) = 2 }}$

Hope it helps you.

To learn more on brainly:

1)Solution of the equation 2p - 15 = 12 - 3p is : *

https://brainly.in/question/47576812

2) Use the Factor Theorem to determine whether or not

factor of the second.

1. X-1; x2 + 2x + 5

2. x + 1; X3 – X-2

3....

https://brainly.in/question/27028616