4. In a hot water heating System, there is cylindrical pipe
of length 28 m and diameter 5 cm Find the total so
radiating
Surface in the system. tas
Sol 4. Height of cylindrical pipe= Length of cylindrical pipe = 28m
Radius of circular end of pipe = diameter/2 = 5/2 cm
= 2.5cm -0.025m!
Now, CSA of cylindrical pipe=2Turh, where = radius
and h= height of the cylinder.
- 2x(2212) x 0.025x28m2
- 4.4 m²
The area of the radiating Surface of the System is 4-4 m?
2
Answers
Answered by
1
Step-by-step explanation:
Answer. Given length = 28 m. diameter = 5 cm then the radius will be r = 5/2 cm = 0.025m. = 4.4 m^2.
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