4. In a sample of FeO when 12% Fe+2 get replaced by Fe3+. The composition of this wustite sample is
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12% Fe2+ are being replaced by Fe3+ . So let there be 100 Fe atoms
And we know for 100 Fe there will be 100 O atoms
So, Initially formula is Fe2+100 O2-100
Now 12% i.e, 12 out of 100 Fe2+ are to be replaced
So amount of charge to replaced 12 x +2 = +24
Now 3+ charge will be provided by 1 Fe3+ atom
+24 charge will be provided by 24/3 = 8 such atoms
So previously after 12 atoms of Fe2+ removed, left Fe2+ = 100-12 = 88
And 8 new Fe atoms join as Fe3+
Hence total Fe = 96
total O = 100
100 O require 96 Fe atoms
1 O require 96/100 = 0.96 Fe atoms
So, the composition will be
Fe0.96O
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