Question

4. In AABC, AD is the median. Show that
AB + BC + AC> 2AD.​

Answer 1

Answer:

Given, △ABC, AD is median of triangle, on side BC

Now, In △ABD,

AB+BD>AD (Sum of two sides of triangle is greater than the third side)

Now, In △ACD,

AC+CD>AD (Sum of two sides of triangle is greater than the third side)

Thus, adding both,

AB+BD+AC+CD>2AD

AB+AC+BC>2AD