4. In an A.P., a=-3, d=0. Find the sum of its first 10 terms.
Answers
Answered by
0
Answer:
gjgsusbsjbsbsbjmsbsusgsbshxgbwu sbsbjw
Answered by
2
Answer:
sum = -30
Step-by-step explanation:
sum of a.p is n/2 [ 2a+(n-1)d]
n = number of terms
a is first term
d is common difference generally a2- a1
in given problem a=-3 and d=0 which means there is no difference among numbers.
given to find sum of first 10 terms
n=10
as per formula 10/2[2(-3)+(10-1)0]
= 5[-6+0]
= 5(-6) = -30
also the a.p will be -3,-3,-3,-3,-3,-3,-3,-3,-3,-3.
by adding it too you get -30.
hope it helps you
mark me brainliest if you like my explanation.
Similar questions