Math, asked by mehtaansh06, 1 month ago

4. In an A.P., a=-3, d=0. Find the sum of its first 10 terms.​

Answers

Answered by hemashinde
0

Answer:

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Answered by saladisrikanth1079
2

Answer:

sum = -30

Step-by-step explanation:

sum of a.p is n/2 [ 2a+(n-1)d]

n = number of terms

a is first term

d is common difference generally a2- a1

in given problem a=-3 and d=0 which means there is no difference among numbers.

given to find sum of first 10 terms

n=10

as per formula 10/2[2(-3)+(10-1)0]

= 5[-6+0]

= 5(-6) = -30

also the a.p will be -3,-3,-3,-3,-3,-3,-3,-3,-3,-3.

by adding it too you get -30.

hope it helps you

mark me brainliest if you like my explanation.

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