Math, asked by VenuRathi, 4 months ago

4. In an isosceles triangle BCD, shown in Fig.3, BE is a median as well as an altitude of a triangle and BC = 29cm and CD = 40cm. What should be the length of BE?​


VenuRathi: pls answer fast
rohit345269: Yes your are correct

Answers

Answered by rohit345269
2

Answer:

BC=7 cm

Step-by-step explanation:

1.Triangle BCD an isosceles triangle

2. To Find BE ?

3. CD =40 cm

4. BC =29 cm

5.As BE is the median it bisects the base into two equal parts As CD is is the base it gets bisected =20cm.

6.so in Triangle BCE By PT THM BE =7 cm

7.so I have found BE =7 cm

8. If any problem tell me mate

9.Make me brainlyeast

Attachments:

VenuRathi: no I solved the answer is 21 and it was asked to find BE not BC by the PT THM it is 21
rohit345269: check question Bro I am correct
rohit345269: I have found BE only
rohit345269: You will understand now with diagram
VenuRathi: no actually my dad is expert in maths but he was not available that time so i post this over here and then asked dad so he solved it for me and that was the answer but thanks for your try !
VenuRathi: I saw your diagram and it is correct but the answer isn't
VenuRathi: see I will tell you 20×20= 400 29×29=841 841-400=441 = 21
Answered by surekhakirodian6
1

Answer:

21

Step-by-step explanation:

square BE=square(29)-square(20)

so,841-400=441=21 square

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