Math, asked by hirasinghdhaliwal14, 1 day ago

4. In how many months will 1020 amount to 1037 at 5/2% simple interest per annum? ​

Answers

Answered by yvidya133
0

Answer:

... Time = 8 months

Step-by-step explanation:

Given :

: Principal (p) = 1020 rupees

:

Amount (A) 1037 rupees

=

Rate%(r) = -%

To Find:

Time(t) =?

According to given question :

As we know that ⇒ A=p+ S. I 0 KB/s

4G

56%

6:16

<

Math 5 points >

:

To Find:

Time(t) = ?

• According to given question :

As we know that

:= A = p + S. I

1037=

=

1020 + si

:

:⇒S.I = 1037

-

1020

:=

S.I 17 rupees

As we know that

S.I=

100

:

1020 x 5 x t 2 x 100 : ⇒17=

0 KB/s

4G

56%

6:16

<

Math

5 points >

As we know that

: S.I= pxrxt 100

1020 x 5 xt 2 x 100 :→ 17 =

17 x 2 x 100

1020 x 5

t

3400

5100

t =

x 12

: t = 8 months

Answered by saritadhuliya2823
0

area - principle + simple interest

1037=1020+ simple interest

simple interest=1037-1020

si. = 17 rupees

time = (100×interest)/(principle×rate)

17×2×100/1020×5 = time

time = 3400/5100×12

time=8 months

Similar questions