Math, asked by pg657526, 18 days ago

37. Simplify / ((cos theta - 2cos^3 theta)/(2sin^3 theta - sin theta)) (b) cot theta (c) sec(theta) (d) cos theta​

Answers

Answered by bhavishyakumar2006
0

Answer:

sinθ−2sin

3

θ

=

cosθ(2cos

2

θ−1)

sinθ(1−2sin

2

θ)

=

cosθ.cos2θ

sinθ.cosθ

=

cosθ

sinθ

=tanθ

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