Question

4 in OE is the bisector of BOD. angle 1=70, find the magnitude of angle 2, angle 3 and angle 4​

Answer 1

According to the figure,

∠COB=∠AOD and

∠AOC=∠BOD=140

o

[ ∵ vertically opposite angles]

We know that,

sum of all the angles around a point =360o

∠BOD+∠AOD+∠AOC+∠COB=360o

∠BOD+∠AOD+∠BOD+∠AOD=360o

2∠BOD+2∠AOD=360o

∠BOD+∠AOD=180o

140+∠AOD=180o

∠AOD=180o −140o

∠AOD=20o

=> ∠COB=20o

∠AOC=∠BOD=140o

∴∠2=∠4=20°

and ∠3=140°

.

Answer 2

Answer:

Post the question properly your question is not proper some values are missing .

Step-by-step explanation:

Btw thanks for the points.