Question

If women weighs 50 kg and the tips of the heel is 10mm2.What is the pressure exerted on the floor by her heel?

Answer 1

Explanation:

Mass of the girl, m=50kg

Diameter of the heel, d=1cm=0.01m

Radius of the heel, r=

2

d

=0.005m

Area of the heel =πr

2

=π×(0.005)

2

=7.85×10

−5

m

2

Force exerted by the heel on the floor:

F=mg

=50×9.8

=490N

Pressure exerted by the heel on the floor:

P=

Area

Force

=490/(7.85×10

−5

)=6.24×10

6

N/m

2

Therefore, the pressure exerted by the heel on the horizontal floor is 6.24×10

6

N/m

2

.

Answer 2

Answer:

P=F/A

50X10/(10/1000X1/2)^2X3.1415926574=6366198Pa

Explanation:

Since pressure is indirectly proportional to the area the smaller the area the greater the pressure.