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In the adjoining figure, ABC and CEF are two triangles where BA is parallel to
CE and AF: AC = 5:8
i. Prove that AADF is similar to ACEF
ii. Find AD ifCE = 6 cm
in. If DE is parallel to BC, find DF: BC
iv. Find area of AADF: area of AABC
А
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Step-by-step explanation:
AB^2+AC^2=BC^2( PYTHAGORAS PROPERTY)
AB^2=BC^2-AC^2
=17^2-15^2
=289-225
AB^2=64
AB=8
area of ABC=1/2×b×h
=1/2×AC×AB
=1/2×15×8
=15×4
=60cmsq
area of ABC=1/2×b×h
60=1/2×BC×AD
60=1/2×17×AD
AD=60×2/17
=120/17
=7.058
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