Find the value of k so that the pair of equations x+2y=5 and 3x+ky+15=0 has
an infinite solution
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ANSWER
The given system of equations can be written as
x+2y−5=0
3x+ky−15=0
This system of equation is of the form
a
1
x+b
1
y+c
1
=0
a
2
x+b
2
y+c
2
=0
where, a
1
=1,b
1
=2,c
1
=−5 and a
2
=3,b
2
=k,c
2
=−15
The given system of equations will have a unique solution, if
3
1
=
k
2
⇒k
=6.
Step-by-step explanation:
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