Question

(4)
In the given figure, ABCD is a parallelogram. AB is produced to P, such that
AB = BP and PQ is drawn parallel to BC to meet AC produced at Q. Given AB - 8
cm, AD = 5 cm, AC = 10 cm.
(i)
Prove that point Cis mid point of AQ.
(ii) Find the perimeter of quadrilateral BCQP.

Answer 1

Answer:

According to the given question....

We know that ,

since, B is the Mid point of AD and

BC is a parallel to PQ

(by conserve mid point Theorem)

BC=1/2 of PQ and C is mid point of AQ

BC=AD ( opposite side of parallogram)

=5cm

=PQ= 2BC

=2×5=10cm

Above show we know that C is a mid point of AQ

Then, Perimeter of BPQC= 8+5+10+10

=33cm. hence proved.........

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