Question

4. In the given figure, LOAB- 30° and LOCB-57º. Find LBOC and LAOC.



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Answer 1

Answer:

∠BOC=∠AOC=60°

Step-by-step explanation:

in figure,

OA=OB=OC(RADIUS)

so,∠OCB=∠OBC

also,∠OBA is 30°

so, ∠ABC=27°

similarly, ∠BAC=27°

⇒∠BAC=∠ABC

⇒AC=BC

⇒∠AOC=∠BOC                       ....(1)

now by ASP in ΔBOA,

∠BOA=120°

∴∠BOC=∠AOC=60°                 (using (1) ).

Answer 2

Answer:

Step-by-step explanation:

OA=OB=OC(RADIUS)

so,angle OCB=angleOBC

also,angle OBA is 30°

so, angle ABC=27°

similarly, angle BAC=27°

angle BAC= angle ABC

AC=BC

angle AOC= angle BOC                       ....(1)

now by ASP in ΔBOA,

angle BOA=120°

angle BOC=angle AOC=60°                 (using (1) ).

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