The present age of A is twice that of B.
sum of their present ages is 33 years.find
the age of A before 5 years.
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GIVEN :
Let the age of B = x
Now the age of A is twice of B i.e., 2x.
Both ages sum = 33
WORKING :
x + 2x = 33
3x = 33, x = 33/3 = 11.
Therefore x = 11.
Now the age of B = 11 and A = 2*11 = 22
Age of A before 5 years = 22-5= 17 years
Let the age of B = x
Now the age of A is twice of B i.e., 2x.
Both ages sum = 33
WORKING :
x + 2x = 33
3x = 33, x = 33/3 = 11.
Therefore x = 11.
Now the age of B = 11 and A = 2*11 = 22
Age of A before 5 years = 22-5= 17 years
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