Question

4. In the given figure, triangle ABC is right-angled at C. E is any
point on BC and EF is perpendicular to AB. G is any point on AB, such that
GH is perpendicular AC. Prove that:
triangleBEF is similiar to triangle GAH​

Answer 1

Answer:

where is the figure gentleman

Answer 2

Answer:

we need the figure only then the question can be answered.. hope u understand..