Question

-4 is a zero of polynomial xsq -x-(2k+2)?find k

Answer 1

Hey Friend ☺

- 4 is the zero of polynomial x^2 - x - ( 2k + 2 )

so

p ( - 4 ) = 0

p ( - 4 ) = x^2 - x - ( 2k + 2 )

》0 = ( - 4 )^2 - ( - 4 ) - ( 2k + 2 )

》0 = 16 + 4 - 2k - 2

》18 = 2k

》k = 18/2

》k = 9

So the value of k is 9

Hope it helps you ..!!

✌

Answer 2

Hey !!

Here is your answer... ⬇⬇⬇

Given :- P (x) = - x^2 - x - ( 2k + 2 )
x = ( - 4 )

To Find :- Value of ( K ).

Solution :- As we have given in question the value of a zero so by putting ( x ) value we can find value of ( K ).

P ( -4 ) = - ( - 4 )^2 - ( -4 ) - ( 2k + 2 )
= 16 - (- 4 ) - 2k - 2
= 16 + 4 - 2k - 2
2k = 20 - 2
2k = 18
k = 18/2
k = 9


Here we get the value of ( K ) is 9.

Hope it helps you....

THANKS ^-^