Question

4 kg of ice at -15 degree celsius are added to 5 kg of water at 15 degree celsius the temperature of the

Answer 1

Answer:

0 ° c

Explanation:

This is because while bringing the 5 kg water to 0°c we need heat equal to ms(dt)= 5(1)(15)= 75joules and for bringing 4 kg ice to 0°c ms(dt)=4(0.5)(-15)= -30 joules

So adding both we get extra of 45 joules which will be consumed by the rest of ice i.e

45=mL, where L is latent heat of fusion

45=x(80)

X=0.5625 kg

So a total of 3.4375 kg of ice and 5.5625kg of water is at 0°c