4 MARKS QUESTIONS
1. In AABC, seg MN || side AC. Seg MN divides
AABC into two parts equal in area. Determine
AM
MB
(HOTS)
Answers
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12
Answer:
In ∆ABC, seg MN || side AC
=> ΔAMN ≈ ∆ABC
=> AM/AB = AN/AC = MN/BC
Area of ΔAMB/ Area of Δ ABC = (AM/MB)²
MN divides ∆ABC into two parts equal in area
=> Area of Δ ABC = 2 Area of ΔAMB
=> Area of ΔAMB/ 2 Area of ΔAMB = (AM/MB)²
=> 1/2 = (AM/MB)²
=> AM/MB = 1/√2
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