Question

4 men and 3 women can finish ajob in 6 days, and 5 men and 7 women can do the samejob in 4 days. How long will 1 man and 1 woman take to do the same work?

Answer 1

Answer:

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Step-by-step explanation:

Let the work be considered to have 12- units.

So 4 m + 3 w can do= 12/6= 2 units in 1- day &

5 m + 7 w can do= 12/4= 3 units in 1- day.

4 m + 3w= 2 …… Eqn--1

5 m+ 7w= 3 …… Eqn--2

[ Eqn--2 x 4] - [Eqn--1 x 5]

=13w= 2 ;

So w= 2/13.

Substituting w= 2/13 we get

m= 5/13

So in 1- day 1 man and 1- woman can do= 2/13 + 5/13= 7/13 units of work.

Therefore 12- units of work will be done by 1- man and 1- woman in

Answer 2

Answer:

let the time taken to complete the work = x days

A.T.Q

( 4 men + 3 women ) * 6 = ( 5 men + 7 women ) * 4

24 men + 18 women = 20 men + 28 women

4 men = 10 women

1 men = 2.5 women

total work = 24 men + 18 women

20 men plus 28 women

1 man + 1 woman = 2.5 women + 1 woman = 3.5

women can do 78/3.5 = 22 ( 2/7 ) days