4 men and 4 women can finish a piece of work jointly in 3days while 2 men and 5 women can finish the same work jointly in 4 days find the time taken by one man alone and that of one women alone to finish the same work
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Answered by
6
Answer:
Let work be complete by men be - X
Let work be complete by women be - Y
4/X + 4/Y = 1/3. / 1/X = A
2/X + 5/Y = 1/4. / 1/Y = B
4a+4b=1/3 (1)
2a+5b=1/4
Multiply EQ 2 by 2
4a+10b= 1/2 (3)
Now you can solve the equation by elimination then put value of b and a like this
1/X = whatever the value of a
1/Y = " " " " " " " "
Thanks if u want me to solve ahead please tell
senthur87:
but in the question the number of days wanted to complete the work.if we assume x,y as work then in what way the time taken is found
Answered by
0
Step-by-step explanation:
let the work done by men in one day X and the work done by a man in one day b y
now we are given
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