4 men and 6women can finish a piece of work in 5days while 3 men and 4women can finish it in 7days .Find the time taken by 1 man done & that of by 1 woman alone
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Hlo!
4/x + 6/y = 1/5
3/x + 4/y = 1/7
let 1/x be u and 1/y be v
then,
4u + 6v = 1/5 20 u+30v =1 ............(1)
3u + 4v = 1/7 21u +28v =1.............(2)
then by elimination method,
21(20u+31v = 1) .
20(21 u+28v =1)
420u -420u +630v - 560 v =21-20
70 v = 1 v = 1/70 and y =70 days
x = 35 days
1 man can do work in 35days
1 woman can do work in 70 days
HOPE IT HELPS YOU
4/x + 6/y = 1/5
3/x + 4/y = 1/7
let 1/x be u and 1/y be v
then,
4u + 6v = 1/5 20 u+30v =1 ............(1)
3u + 4v = 1/7 21u +28v =1.............(2)
then by elimination method,
21(20u+31v = 1) .
20(21 u+28v =1)
420u -420u +630v - 560 v =21-20
70 v = 1 v = 1/70 and y =70 days
x = 35 days
1 man can do work in 35days
1 woman can do work in 70 days
HOPE IT HELPS YOU
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