the sum of two digit number and the number obtained by reversing the order of its digit is 99 if the digit differ by 3 find the number
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Answered by
2
it may be 33
hope it helps you
hope it helps you
Answered by
7
Let the first digit (one's) = x
Therefore the second digit (ten's)
= x-3
Number = 10×(x-3) + 1× x
= 10x -30 +x
= 30 + 9x
On reversing the digits
One's digit = x-3
Ten's digit = x
ATQ
x-3 + x = 99
2x = 102
x = 51
Therefore actual number = 30 + 9(2)
= 48
Therefore the second digit (ten's)
= x-3
Number = 10×(x-3) + 1× x
= 10x -30 +x
= 30 + 9x
On reversing the digits
One's digit = x-3
Ten's digit = x
ATQ
x-3 + x = 99
2x = 102
x = 51
Therefore actual number = 30 + 9(2)
= 48
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