4 men can do as much work in 7 days and 6 women in the same time find the number of days required to finish the work by 8 men and 9 women working together.
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Answered by
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given 4 men can do as much work in 7 days i.e.,
7*4 men= 1work
=>1 man=1/28 work.This is the work done by one man in one day.
Similarly 6 women take the same time i.e., 7 days
=>6*7 women = 1 work
=>1 women= 1/42 work.This is the work done by 1 woman in 1 day
number of days required to finish the work by 8 men and 9 women working together is as follows
let no.of days taken to complete work be 'x'
x(8(1/28)+9(1/42))=1
On solving this we get x= 2
Hence 2 days were required to complete the work with the help of 8 men and 6 women.
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