4 men throw a die each simultaneously. find the probability that at least 2 people get the same number
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Answered by
4
Answer: 13/18
We will solve this in an easy to understand stepwise manner. Here we go:
A person will throw a dice, and he will get a number. Now, the probability that the second person will not get the same number is 5/6 (Right? If you don't understand how, ask in the comments).
Similarly, the probability that the third person will not get the same number is 4/6 and that of the fourth person is 3/6.
Now, what is the probability that all people get different numbers?
1 × 5/6 × 4/6 × 3/6 = 5/18
∴ P(at least 2 people get the same number) = 1 - 5/18 = 13/18
We will solve this in an easy to understand stepwise manner. Here we go:
A person will throw a dice, and he will get a number. Now, the probability that the second person will not get the same number is 5/6 (Right? If you don't understand how, ask in the comments).
Similarly, the probability that the third person will not get the same number is 4/6 and that of the fourth person is 3/6.
Now, what is the probability that all people get different numbers?
1 × 5/6 × 4/6 × 3/6 = 5/18
∴ P(at least 2 people get the same number) = 1 - 5/18 = 13/18
Answered by
0
probability of people get different no....
=1×5/6×4/6×3/6
=60/216
=30/108=15/54=5/18
=5/18
p (at least 2 people get same number)
=1-5/18
=13/18
...★★★★★★
=1×5/6×4/6×3/6
=60/216
=30/108=15/54=5/18
=5/18
p (at least 2 people get same number)
=1-5/18
=13/18
...★★★★★★
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