Question

4 moles of A are mixed with 4 moles of B. At, equilibrium for the reaction A+B⇄C+D, 2 moles of C and D are formed. The equilibrium constant for the reaction will be:

Answer 1

                          A      +      B      ⇄      C      +       D

initial mole  -       4             4                0               0
at equilibrium -   4-x          4-x             x=2           x=2
so final moles -   2             2                  2              2

the equilibrium constant = [C][D] / [A][B] = [2][2] / [2][2] = 1

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Answer 2

Answer:

one is the right answer of this question

Explanation:

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