4. My age ten years ago was four less than two thirds of my current age. How old was I ten years ago
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If the present age is y, then n times the present age = ny.
If the present age is x, then age n years later/hence = x + n.
If the present age is x, then age n years ago = x – n.
The ages in a ratio a: b will be ax and bx.
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Answer:
8
Step-by-step explanation:
=> x - 10 = 2x/3 -4
=> x-6 = 2x/3
=> 3x - 18 = 2x
=> x= 18
So , current age is 18.
age 10 years ago = 18-10 = 8 .
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